Optimal. Leaf size=175 \[ \frac {i f \sinh ^2(c+d x)}{4 a d^2}-\frac {f \sinh (c+d x)}{a d^2}+\frac {2 i f \log \left (\cosh \left (\frac {c}{2}+\frac {d x}{2}+\frac {i \pi }{4}\right )\right )}{a d^2}+\frac {(e+f x) \cosh (c+d x)}{a d}-\frac {i (e+f x) \tanh \left (\frac {c}{2}+\frac {d x}{2}+\frac {i \pi }{4}\right )}{a d}-\frac {i (e+f x) \sinh (c+d x) \cosh (c+d x)}{2 a d}+\frac {3 i e x}{2 a}+\frac {3 i f x^2}{4 a} \]
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Rubi [A] time = 0.26, antiderivative size = 175, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.241, Rules used = {5557, 3310, 3296, 2637, 3318, 4184, 3475} \[ \frac {i f \sinh ^2(c+d x)}{4 a d^2}-\frac {f \sinh (c+d x)}{a d^2}+\frac {2 i f \log \left (\cosh \left (\frac {c}{2}+\frac {d x}{2}+\frac {i \pi }{4}\right )\right )}{a d^2}+\frac {(e+f x) \cosh (c+d x)}{a d}-\frac {i (e+f x) \tanh \left (\frac {c}{2}+\frac {d x}{2}+\frac {i \pi }{4}\right )}{a d}-\frac {i (e+f x) \sinh (c+d x) \cosh (c+d x)}{2 a d}+\frac {3 i e x}{2 a}+\frac {3 i f x^2}{4 a} \]
Antiderivative was successfully verified.
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Rule 2637
Rule 3296
Rule 3310
Rule 3318
Rule 3475
Rule 4184
Rule 5557
Rubi steps
\begin {align*} \int \frac {(e+f x) \sinh ^3(c+d x)}{a+i a \sinh (c+d x)} \, dx &=i \int \frac {(e+f x) \sinh ^2(c+d x)}{a+i a \sinh (c+d x)} \, dx-\frac {i \int (e+f x) \sinh ^2(c+d x) \, dx}{a}\\ &=-\frac {i (e+f x) \cosh (c+d x) \sinh (c+d x)}{2 a d}+\frac {i f \sinh ^2(c+d x)}{4 a d^2}+\frac {i \int (e+f x) \, dx}{2 a}+\frac {\int (e+f x) \sinh (c+d x) \, dx}{a}-\int \frac {(e+f x) \sinh (c+d x)}{a+i a \sinh (c+d x)} \, dx\\ &=\frac {i e x}{2 a}+\frac {i f x^2}{4 a}+\frac {(e+f x) \cosh (c+d x)}{a d}-\frac {i (e+f x) \cosh (c+d x) \sinh (c+d x)}{2 a d}+\frac {i f \sinh ^2(c+d x)}{4 a d^2}-i \int \frac {e+f x}{a+i a \sinh (c+d x)} \, dx+\frac {i \int (e+f x) \, dx}{a}-\frac {f \int \cosh (c+d x) \, dx}{a d}\\ &=\frac {3 i e x}{2 a}+\frac {3 i f x^2}{4 a}+\frac {(e+f x) \cosh (c+d x)}{a d}-\frac {f \sinh (c+d x)}{a d^2}-\frac {i (e+f x) \cosh (c+d x) \sinh (c+d x)}{2 a d}+\frac {i f \sinh ^2(c+d x)}{4 a d^2}-\frac {i \int (e+f x) \csc ^2\left (\frac {1}{2} \left (i c+\frac {\pi }{2}\right )+\frac {i d x}{2}\right ) \, dx}{2 a}\\ &=\frac {3 i e x}{2 a}+\frac {3 i f x^2}{4 a}+\frac {(e+f x) \cosh (c+d x)}{a d}-\frac {f \sinh (c+d x)}{a d^2}-\frac {i (e+f x) \cosh (c+d x) \sinh (c+d x)}{2 a d}+\frac {i f \sinh ^2(c+d x)}{4 a d^2}-\frac {i (e+f x) \tanh \left (\frac {c}{2}+\frac {i \pi }{4}+\frac {d x}{2}\right )}{a d}+\frac {(i f) \int \coth \left (\frac {c}{2}-\frac {i \pi }{4}+\frac {d x}{2}\right ) \, dx}{a d}\\ &=\frac {3 i e x}{2 a}+\frac {3 i f x^2}{4 a}+\frac {(e+f x) \cosh (c+d x)}{a d}+\frac {2 i f \log \left (\cosh \left (\frac {c}{2}+\frac {i \pi }{4}+\frac {d x}{2}\right )\right )}{a d^2}-\frac {f \sinh (c+d x)}{a d^2}-\frac {i (e+f x) \cosh (c+d x) \sinh (c+d x)}{2 a d}+\frac {i f \sinh ^2(c+d x)}{4 a d^2}-\frac {i (e+f x) \tanh \left (\frac {c}{2}+\frac {i \pi }{4}+\frac {d x}{2}\right )}{a d}\\ \end {align*}
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Mathematica [A] time = 1.79, size = 325, normalized size = 1.86 \[ \frac {\left (\cosh \left (\frac {1}{2} (c+d x)\right )+i \sinh \left (\frac {1}{2} (c+d x)\right )\right ) \left (\cosh \left (\frac {1}{2} (c+d x)\right ) \left (2 \left (-3 c^2 f-d (e+f x) \sinh (2 (c+d x))+6 c d e+4 i f \sinh (c+d x)+8 i f \tan ^{-1}\left (\tanh \left (\frac {1}{2} (c+d x)\right )\right )+4 f \log (\cosh (c+d x))-4 i c f+6 d^2 e x+3 d^2 f x^2-4 i d f x\right )-8 i d (e+f x) \cosh (c+d x)+f \cosh (2 (c+d x))\right )+\sinh \left (\frac {1}{2} (c+d x)\right ) \left (8 d (e+f x) \cosh (c+d x)+i \left (f \cosh (2 (c+d x))+2 \left (-3 c^2 f-d (e+f x) \sinh (2 (c+d x))+6 c d e+4 i f \sinh (c+d x)+8 i f \tan ^{-1}\left (\tanh \left (\frac {1}{2} (c+d x)\right )\right )+4 f \log (\cosh (c+d x))-4 i c f+6 d^2 e x+3 d^2 f x^2+8 i d e+4 i d f x\right )\right )\right )\right )}{8 a d^2 (\sinh (c+d x)-i)} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.50, size = 227, normalized size = 1.30 \[ \frac {2 \, d f x + 2 \, d e + {\left (-2 i \, d f x - 2 i \, d e + i \, f\right )} e^{\left (5 \, d x + 5 \, c\right )} + {\left (6 \, d f x + 6 \, d e - 7 \, f\right )} e^{\left (4 \, d x + 4 \, c\right )} + {\left (12 i \, d^{2} f x^{2} - 8 i \, d e + {\left (24 i \, d^{2} e - 40 i \, d f\right )} x + 8 i \, f\right )} e^{\left (3 \, d x + 3 \, c\right )} + 4 \, {\left (3 \, d^{2} f x^{2} + 10 \, d e + 2 \, {\left (3 \, d^{2} e + d f\right )} x + 2 \, f\right )} e^{\left (2 \, d x + 2 \, c\right )} + {\left (-6 i \, d f x - 6 i \, d e - 7 i \, f\right )} e^{\left (d x + c\right )} + {\left (32 i \, f e^{\left (3 \, d x + 3 \, c\right )} + 32 \, f e^{\left (2 \, d x + 2 \, c\right )}\right )} \log \left (e^{\left (d x + c\right )} - i\right ) + f}{16 \, a d^{2} e^{\left (3 \, d x + 3 \, c\right )} - 16 i \, a d^{2} e^{\left (2 \, d x + 2 \, c\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.50, size = 355, normalized size = 2.03 \[ \frac {12 i \, d^{2} f x^{2} e^{\left (3 \, d x + 4 \, c\right )} + 12 \, d^{2} f x^{2} e^{\left (2 \, d x + 3 \, c\right )} - 2 i \, d f x e^{\left (5 \, d x + 6 \, c\right )} + 6 \, d f x e^{\left (4 \, d x + 5 \, c\right )} + 24 i \, d^{2} x e^{\left (3 \, d x + 4 \, c + 1\right )} - 40 i \, d f x e^{\left (3 \, d x + 4 \, c\right )} + 24 \, d^{2} x e^{\left (2 \, d x + 3 \, c + 1\right )} + 8 \, d f x e^{\left (2 \, d x + 3 \, c\right )} - 6 i \, d f x e^{\left (d x + 2 \, c\right )} + 2 \, d f x e^{c} + 32 i \, f e^{\left (3 \, d x + 4 \, c\right )} \log \left (e^{\left (d x + c\right )} - i\right ) + 32 \, f e^{\left (2 \, d x + 3 \, c\right )} \log \left (e^{\left (d x + c\right )} - i\right ) - 2 i \, d e^{\left (5 \, d x + 6 \, c + 1\right )} + i \, f e^{\left (5 \, d x + 6 \, c\right )} + 6 \, d e^{\left (4 \, d x + 5 \, c + 1\right )} - 7 \, f e^{\left (4 \, d x + 5 \, c\right )} - 8 i \, d e^{\left (3 \, d x + 4 \, c + 1\right )} + 8 i \, f e^{\left (3 \, d x + 4 \, c\right )} + 40 \, d e^{\left (2 \, d x + 3 \, c + 1\right )} + 8 \, f e^{\left (2 \, d x + 3 \, c\right )} - 6 i \, d e^{\left (d x + 2 \, c + 1\right )} - 7 i \, f e^{\left (d x + 2 \, c\right )} + 2 \, d e^{\left (c + 1\right )} + f e^{c}}{16 \, {\left (a d^{2} e^{\left (3 \, d x + 4 \, c\right )} - i \, a d^{2} e^{\left (2 \, d x + 3 \, c\right )}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.18, size = 197, normalized size = 1.13 \[ \frac {3 i f \,x^{2}}{4 a}+\frac {3 i e x}{2 a}-\frac {i \left (2 d f x +2 d e -f \right ) {\mathrm e}^{2 d x +2 c}}{16 a \,d^{2}}+\frac {\left (d f x +d e -f \right ) {\mathrm e}^{d x +c}}{2 a \,d^{2}}+\frac {\left (d f x +d e +f \right ) {\mathrm e}^{-d x -c}}{2 a \,d^{2}}+\frac {i \left (2 d f x +2 d e +f \right ) {\mathrm e}^{-2 d x -2 c}}{16 a \,d^{2}}-\frac {2 i f x}{a d}-\frac {2 i f c}{a \,d^{2}}+\frac {2 f x +2 e}{d a \left ({\mathrm e}^{d x +c}-i\right )}+\frac {2 i f \ln \left ({\mathrm e}^{d x +c}-i\right )}{a \,d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.71, size = 215, normalized size = 1.23 \[ {\mathrm {e}}^{-c-d\,x}\,\left (\frac {f+d\,e}{2\,a\,d^2}+\frac {f\,x}{2\,a\,d}\right )+{\mathrm {e}}^{-2\,c-2\,d\,x}\,\left (\frac {\left (f+2\,d\,e\right )\,1{}\mathrm {i}}{16\,a\,d^2}+\frac {f\,x\,1{}\mathrm {i}}{8\,a\,d}\right )+{\mathrm {e}}^{2\,c+2\,d\,x}\,\left (\frac {\left (f-2\,d\,e\right )\,1{}\mathrm {i}}{16\,a\,d^2}-\frac {f\,x\,1{}\mathrm {i}}{8\,a\,d}\right )-{\mathrm {e}}^{c+d\,x}\,\left (\frac {f-d\,e}{2\,a\,d^2}-\frac {f\,x}{2\,a\,d}\right )+\frac {f\,x^2\,3{}\mathrm {i}}{4\,a}+\frac {2\,\left (e+f\,x\right )}{a\,d\,\left ({\mathrm {e}}^{c+d\,x}-\mathrm {i}\right )}-\frac {x\,\left (4\,f-3\,d\,e\right )\,1{}\mathrm {i}}{2\,a\,d}+\frac {f\,\ln \left ({\mathrm {e}}^{d\,x}\,{\mathrm {e}}^c-\mathrm {i}\right )\,2{}\mathrm {i}}{a\,d^2} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.93, size = 410, normalized size = 2.34 \[ \frac {2 i e e^{c} + 2 i f x e^{c}}{- a d e^{c} + i a d e^{- d x}} + \begin {cases} \frac {\left (\left (512 a^{3} d^{7} e e^{2 c} + 512 a^{3} d^{7} f x e^{2 c} + 512 a^{3} d^{6} f e^{2 c}\right ) e^{- d x} + \left (512 a^{3} d^{7} e e^{4 c} + 512 a^{3} d^{7} f x e^{4 c} - 512 a^{3} d^{6} f e^{4 c}\right ) e^{d x} + \left (128 i a^{3} d^{7} e e^{c} + 128 i a^{3} d^{7} f x e^{c} + 64 i a^{3} d^{6} f e^{c}\right ) e^{- 2 d x} + \left (- 128 i a^{3} d^{7} e e^{5 c} - 128 i a^{3} d^{7} f x e^{5 c} + 64 i a^{3} d^{6} f e^{5 c}\right ) e^{2 d x}\right ) e^{- 3 c}}{1024 a^{4} d^{8}} & \text {for}\: 1024 a^{4} d^{8} e^{3 c} \neq 0 \\\frac {x^{2} \left (- i f e^{4 c} + 2 f e^{3 c} - 2 f e^{c} - i f\right ) e^{- 2 c}}{8 a} + \frac {x \left (- i e e^{4 c} + 2 e e^{3 c} - 2 e e^{c} - i e\right ) e^{- 2 c}}{4 a} & \text {otherwise} \end {cases} + \frac {3 i f x^{2}}{4 a} + \frac {x \left (3 i d e + 4 i f\right )}{2 a d} + \frac {2 i f \log {\left (i e^{c} + e^{- d x} \right )}}{a d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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